Using "like" wildcard in prepared statement

I am using prepared statements to execute mysql database queries. And I want to implement a search functionality based on a keyword of sorts.

For that I need to use LIKE keyword, that much I know. And I have also used prepared statements before, but I do not know how to use it with LIKE because from the following code where would I add the ‘keyword%’?

Can I directly use it in the pstmt.setString(1, notes) as (1, notes+”%”) or something like that. I see a lot of posts on this on the web but no good answer anywhere.

PreparedStatement pstmt = con.prepareStatement(
      "SELECT * FROM analysis WHERE notes like ?");
pstmt.setString(1, notes);
ResultSet rs = pstmt.executeQuery();

You need to set it in the value itself, not in the prepared statement SQL string.

So, this should do for a prefix-match:

notes = notes
    .replace("!", "!!")
    .replace("%", "!%")
    .replace("_", "!_")
    .replace("[", "![");
PreparedStatement pstmt = con.prepareStatement(
        "SELECT * FROM analysis WHERE notes LIKE ? ESCAPE '!'");
pstmt.setString(1, notes + "%");

or a suffix-match:

pstmt.setString(1, "%" + notes);

or a global match:

pstmt.setString(1, "%" + notes + "%");

Make sure that you don’t put these quotes ” like here, as they will cause an exception.

pstmt.setString(1,"'%"+ notes + "%'");

Rather code it like this:

PreparedStatement pstmt = con.prepareStatement(
    "SELECT * FROM analysis WHERE notes like ?");
pstmt.setString(1, notes + "%");`
PreparedStatement ps = cn.prepareStatement("Select * from Users where User_FirstName LIKE ?");
ps.setString(1, name + '%');

Try this out.